Base | Representation |
---|---|
bin | 11101100011110010111011… |
… | …110111100010000001111111 |
3 | 122001022012001001210110100202 |
4 | 131203302323313202001333 |
5 | 114014433044313341111 |
6 | 1140254353344514115 |
7 | 36245265014310524 |
oct | 3543627367420177 |
9 | 561265031713322 |
10 | 130003222012031 |
11 | 38472069715595 |
12 | 126b75b401b93b |
13 | 5770335c5cb94 |
14 | 241629207714b |
15 | 1006a37393b3b |
hex | 763cbbde207f |
130003222012031 has 4 divisors (see below), whose sum is σ = 130041582364200. Its totient is φ = 129964861659864.
The previous prime is 130003222011973. The next prime is 130003222012087. The reversal of 130003222012031 is 130210222300031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130003222012031 - 26 = 130003222011967 is a prime.
It is a super-2 number, since 2×1300032220120312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130003222011994 and 130003222012012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130003222012931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19180171001 + ... + 19180177778.
It is an arithmetic number, because the mean of its divisors is an integer number (32510395591050).
Almost surely, 2130003222012031 is an apocalyptic number.
130003222012031 is a deficient number, since it is larger than the sum of its proper divisors (38360352169).
130003222012031 is an equidigital number, since it uses as much as digits as its factorization.
130003222012031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38360352168.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 130003222012031 its reverse (130210222300031), we get a palindrome (260213444312062).
The spelling of 130003222012031 in words is "one hundred thirty trillion, three billion, two hundred twenty-two million, twelve thousand, thirty-one".
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