Base | Representation |
---|---|
bin | 11101100011110010111011… |
… | …110111100010010000000011 |
3 | 122001022012001001210111121002 |
4 | 131203302323313202100003 |
5 | 114014433044313403211 |
6 | 1140254353344522215 |
7 | 36245265014313251 |
oct | 3543627367422003 |
9 | 561265031714532 |
10 | 130003222012931 |
11 | 38472069716233 |
12 | 126b75b402036b |
13 | 5770335c60407 |
14 | 24162920775d1 |
15 | 1006a3739403b |
hex | 763cbbde2403 |
130003222012931 has 2 divisors, whose sum is σ = 130003222012932. Its totient is φ = 130003222012930.
The previous prime is 130003222012919. The next prime is 130003222012957. The reversal of 130003222012931 is 139210222300031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130003222012931 is a prime.
It is a super-2 number, since 2×1300032220129312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130003222012894 and 130003222012903.
It is not a weakly prime, because it can be changed into another prime (130002222012931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001611006465 + 65001611006466.
It is an arithmetic number, because the mean of its divisors is an integer number (65001611006466).
Almost surely, 2130003222012931 is an apocalyptic number.
130003222012931 is a deficient number, since it is larger than the sum of its proper divisors (1).
130003222012931 is an equidigital number, since it uses as much as digits as its factorization.
130003222012931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 29.
Adding to 130003222012931 its reverse (139210222300031), we get a palindrome (269213444312962).
The spelling of 130003222012931 in words is "one hundred thirty trillion, three billion, two hundred twenty-two million, twelve thousand, nine hundred thirty-one".
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