Base | Representation |
---|---|
bin | 111100100010011001… |
… | …1010001101011100011 |
3 | 110102120011011110220201 |
4 | 1321010303101223203 |
5 | 4112221321430311 |
6 | 135420034050031 |
7 | 12251413625245 |
oct | 1710463215343 |
9 | 412504143821 |
10 | 130003311331 |
11 | 50152530a73 |
12 | 21241a19917 |
13 | c34a793aba |
14 | 6413acc095 |
15 | 35ad2b99c1 |
hex | 1e44cd1ae3 |
130003311331 has 8 divisors (see below), whose sum is σ = 131594737904. Its totient is φ = 128417011200.
The previous prime is 130003311289. The next prime is 130003311341. The reversal of 130003311331 is 133113300031.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130003311331 - 213 = 130003303139 is a prime.
It is a super-2 number, since 2×1300033113312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130003311299 and 130003311308.
It is not an unprimeable number, because it can be changed into a prime (130003311341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1230570 + ... + 1332031.
It is an arithmetic number, because the mean of its divisors is an integer number (16449342238).
Almost surely, 2130003311331 is an apocalyptic number.
130003311331 is a deficient number, since it is larger than the sum of its proper divisors (1591426573).
130003311331 is an equidigital number, since it uses as much as digits as its factorization.
130003311331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2563221.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 130003311331 its reverse (133113300031), we get a palindrome (263116611362).
It can be divided in two parts, 13000 and 3311331, that added together give a triangular number (3324331 = T2578).
The spelling of 130003311331 in words is "one hundred thirty billion, three million, three hundred eleven thousand, three hundred thirty-one".
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