Base | Representation |
---|---|
bin | 1011110100101110010001… |
… | …0111010000100111101100 |
3 | 1201000211022101120112110021 |
4 | 2331023210113100213230 |
5 | 3200444310444342312 |
6 | 43352145152051524 |
7 | 2511151042421311 |
oct | 275134427204754 |
9 | 51024271515407 |
10 | 13000402340332 |
11 | 4162492223a70 |
12 | 155b694533ba4 |
13 | 733c18139014 |
14 | 32d319638d08 |
15 | 178284b5dc07 |
hex | bd2e45d09ec |
13000402340332 has 48 divisors (see below), whose sum is σ = 24836129305344. Its totient is φ = 5905184904000.
The previous prime is 13000402340309. The next prime is 13000402340347. The reversal of 13000402340332 is 23304320400031.
It is a super-2 number, since 2×130004023403322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13000402340297 and 13000402340306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 441380118 + ... + 441409570.
It is an arithmetic number, because the mean of its divisors is an integer number (517419360528).
Almost surely, 213000402340332 is an apocalyptic number.
It is an amenable number.
13000402340332 is a deficient number, since it is larger than the sum of its proper divisors (11835726965012).
13000402340332 is a wasteful number, since it uses less digits than its factorization.
13000402340332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36070 (or 36068 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13000402340332 its reverse (23304320400031), we get a palindrome (36304722740363).
The spelling of 13000402340332 in words is "thirteen trillion, four hundred two million, three hundred forty thousand, three hundred thirty-two".
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