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1300041042242 = 25091277054069
BaseRepresentation
bin10010111010110000011…
…111000000100101000010
311121021122002120121121012
4102322300133000211002
5132244441001322432
62433121451200522
7162632141350145
oct22726037004502
94537562517535
101300041042242
114613873048a8
1218bb59146142
13957937674a7
1446ccabd005c
1523c3c830cb2
hex12eb07c0942

1300041042242 has 8 divisors (see below), whose sum is σ = 1953892727100. Its totient is φ = 648743466544.

The previous prime is 1300041042233. The next prime is 1300041042247. The reversal of 1300041042242 is 2422401400031.

It can be written as a sum of positive squares in 2 ways, for example, as 1184834427001 + 115206615241 = 1088501^2 + 339421^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not an unprimeable number, because it can be changed into a prime (1300041042247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638526017 + ... + 638528052.

Almost surely, 21300041042242 is an apocalyptic number.

1300041042242 is a deficient number, since it is larger than the sum of its proper divisors (653851684858).

1300041042242 is a wasteful number, since it uses less digits than its factorization.

1300041042242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1277054580.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 1300041042242 its reverse (2422401400031), we get a palindrome (3722442442273).

The spelling of 1300041042242 in words is "one trillion, three hundred billion, forty-one million, forty-two thousand, two hundred forty-two".

Divisors: 1 2 509 1018 1277054069 2554108138 650020521121 1300041042242