1300041042241 has 4 divisors (see below), whose sum is σ = 1306573912000. Its totient is φ = 1293508172484.

The previous prime is 1300041042233. The next prime is 1300041042247. The reversal of 1300041042241 is 1422401400031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300041042241 - 2³ = 1300041042233 is a prime.

It is a super-2 number, since 2×1300041042241² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300041042247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3266434581 + ... + 3266434978.

It is an arithmetic number, because the mean of its divisors is an integer number (326643478000).

Almost surely, 2^{1300041042241} is an apocalyptic number.

It is an amenable number.

1300041042241 is a deficient number, since it is larger than the sum of its proper divisors (6532869759).

1300041042241 is an equidigital number, since it uses as much as digits as its factorization.

1300041042241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6532869758.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 1300041042241 its reverse (1422401400031), we get a palindrome (2722442442272).

The spelling of 1300041042241 in words is "one trillion, three hundred billion, forty-one million, forty-two thousand, two hundred forty-one".