1300041042353 has 2 divisors, whose sum is σ = 1300041042354. Its totient is φ = 1300041042352.

The previous prime is 1300041042331. The next prime is 1300041042431. The reversal of 1300041042353 is 3532401400031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1252716085504 + 47324956849 = 1119248^2 + 217543^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300041042353 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300041041353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650020521176 + 650020521177.

It is an arithmetic number, because the mean of its divisors is an integer number (650020521177).

Almost surely, 2^{1300041042353} is an apocalyptic number.

It is an amenable number.

1300041042353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300041042353 is an equidigital number, since it uses as much as digits as its factorization.

1300041042353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 1300041042353 its reverse (3532401400031), we get a palindrome (4832442442384).

The spelling of 1300041042353 in words is "one trillion, three hundred billion, forty-one million, forty-two thousand, three hundred fifty-three".