1300042875409 has 2 divisors, whose sum is σ = 1300042875410. Its totient is φ = 1300042875408.

The previous prime is 1300042875403. The next prime is 1300042875473. The reversal of 1300042875409 is 9045782400031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 726619856400 + 573423019009 = 852420^2 + 757247^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300042875409 - 2⁵ = 1300042875377 is a prime.

It is a super-2 number, since 2×1300042875409² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1300042875403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650021437704 + 650021437705.

It is an arithmetic number, because the mean of its divisors is an integer number (650021437705).

Almost surely, 2^{1300042875409} is an apocalyptic number.

It is an amenable number.

1300042875409 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300042875409 is an equidigital number, since it uses as much as digits as its factorization.

1300042875409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 43.

The spelling of 1300042875409 in words is "one trillion, three hundred billion, forty-two million, eight hundred seventy-five thousand, four hundred nine".