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1300055513 is a prime number
BaseRepresentation
bin100110101111101…
…0100010111011001
310100121021122220012
41031133110113121
510130303234023
6333000411305
744134201211
oct11537242731
93317248805
101300055513
11607935a49
12303476b35
13179457323
14c4937241
1579201978
hex4d7d45d9

1300055513 has 2 divisors, whose sum is σ = 1300055514. Its totient is φ = 1300055512.

The previous prime is 1300055509. The next prime is 1300055539. The reversal of 1300055513 is 3155500031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1208049049 + 92006464 = 34757^2 + 9592^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300055513 - 22 = 1300055509 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300057513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650027756 + 650027757.

It is an arithmetic number, because the mean of its divisors is an integer number (650027757).

Almost surely, 21300055513 is an apocalyptic number.

It is an amenable number.

1300055513 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300055513 is an equidigital number, since it uses as much as digits as its factorization.

1300055513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1125, while the sum is 23.

The square root of 1300055513 is about 36056.2825732215. The cubic root of 1300055513 is about 1091.4084178382.

Adding to 1300055513 its reverse (3155500031), we get a palindrome (4455555544).

The spelling of 1300055513 in words is "one billion, three hundred million, fifty-five thousand, five hundred thirteen".