1300065013 has 4 divisors (see below), whose sum is σ = 1400070028. Its totient is φ = 1200060000.

The previous prime is 1300064971. The next prime is 1300065077. The reversal of 1300065013 is 3105600031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3105600031 = 53 ⋅58596227.

It can be written as a sum of positive squares in 2 ways, for example, as 860659569 + 439405444 = 29337^2 + 20962^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300065013 - 2⁹ = 1300064501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300065313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50002488 + ... + 50002513.

It is an arithmetic number, because the mean of its divisors is an integer number (350017507).

Almost surely, 2^1300065013 is an apocalyptic number.

1300065013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1300065013 is a deficient number, since it is larger than the sum of its proper divisors (100005015).

1300065013 is a wasteful number, since it uses less digits than its factorization.

1300065013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100005014.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 1300065013 is about 36056.4143114647. The cubic root of 1300065013 is about 1091.4110762772.

Adding to 1300065013 its reverse (3105600031), we get a palindrome (4405665044).

The spelling of 1300065013 in words is "one billion, three hundred million, sixty-five thousand, thirteen".