Base | Representation |
---|---|
bin | 1011110100110000100000… |
… | …0011110001010110110001 |
3 | 1201000212212010110022222222 |
4 | 2331030020003301112301 |
5 | 3201002022302230223 |
6 | 43352324424010425 |
7 | 2511201633635663 |
oct | 275141003612661 |
9 | 51025763408888 |
10 | 13001001211313 |
11 | 416276a280665 |
12 | 155b821000a15 |
13 | 733cb222aa4b |
14 | 32d374daa533 |
15 | 1782bc5070c8 |
hex | bd3080f15b1 |
13001001211313 has 16 divisors (see below), whose sum is σ = 14203149448320. Its totient is φ = 11862259901184.
The previous prime is 13001001211301. The next prime is 13001001211337. The reversal of 13001001211313 is 31311210010031.
It is a cyclic number.
It is not a de Polignac number, because 13001001211313 - 228 = 13000732775857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13001001211291 and 13001001211300.
It is not an unprimeable number, because it can be changed into a prime (13001001211613) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117364856 + ... + 117475577.
It is an arithmetic number, because the mean of its divisors is an integer number (887696840520).
Almost surely, 213001001211313 is an apocalyptic number.
It is an amenable number.
13001001211313 is a deficient number, since it is larger than the sum of its proper divisors (1202148237007).
13001001211313 is a wasteful number, since it uses less digits than its factorization.
13001001211313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234840568.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13001001211313 its reverse (31311210010031), we get a palindrome (44312211221344).
The spelling of 13001001211313 in words is "thirteen trillion, one billion, one million, two hundred eleven thousand, three hundred thirteen".
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