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234840433 is a prime number
BaseRepresentation
bin11011111111101…
…10000101110001
3121100220010111211
431333312011301
5440104343213
635145240121
75551052662
oct1577660561
9540803454
10234840433
1111061a103
1266793041
1339865549
1423291369
151593c53d
hexdff6171

234840433 has 2 divisors, whose sum is σ = 234840434. Its totient is φ = 234840432.

The previous prime is 234840413. The next prime is 234840451. The reversal of 234840433 is 334048432.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 231557089 + 3283344 = 15217^2 + 1812^2 .

It is a cyclic number.

It is not a de Polignac number, because 234840433 - 25 = 234840401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 234840395 and 234840404.

It is not a weakly prime, because it can be changed into another prime (234840413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117420216 + 117420217.

It is an arithmetic number, because the mean of its divisors is an integer number (117420217).

Almost surely, 2234840433 is an apocalyptic number.

It is an amenable number.

234840433 is a deficient number, since it is larger than the sum of its proper divisors (1).

234840433 is an equidigital number, since it uses as much as digits as its factorization.

234840433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 31.

The square root of 234840433 is about 15324.5043312989. The cubic root of 234840433 is about 616.9608754711.

Adding to 234840433 its reverse (334048432), we get a palindrome (568888865).

The spelling of 234840433 in words is "two hundred thirty-four million, eight hundred forty thousand, four hundred thirty-three".