1300100121213 has 4 divisors (see below), whose sum is σ = 1733466828288. Its totient is φ = 866733414140.

The previous prime is 1300100121193. The next prime is 1300100121241. The reversal of 1300100121213 is 3121210010031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300100121213 - 2¹⁷ = 1300099990141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300100121192 and 1300100121201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300100121253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216683353533 + ... + 216683353538.

It is an arithmetic number, because the mean of its divisors is an integer number (433366707072).

Almost surely, 2^{1300100121213} is an apocalyptic number.

It is an amenable number.

1300100121213 is a deficient number, since it is larger than the sum of its proper divisors (433366707075).

1300100121213 is an equidigital number, since it uses as much as digits as its factorization.

1300100121213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433366707074.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1300100121213 its reverse (3121210010031), we get a palindrome (4421310131244).

The spelling of 1300100121213 in words is "one trillion, three hundred billion, one hundred million, one hundred twenty-one thousand, two hundred thirteen".