Base | Representation |
---|---|
bin | 11000001101110101… |
… | …11001010101110010 |
3 | 1020120001200110020120 |
4 | 30012322321111302 |
5 | 203111224120102 |
6 | 5550024351110 |
7 | 640114466631 |
oct | 140672712562 |
9 | 36501613216 |
10 | 13001004402 |
11 | 5571801041 |
12 | 262a015496 |
13 | 12c2663c19 |
14 | 8b494b518 |
15 | 51159e6bc |
hex | 306eb9572 |
13001004402 has 16 divisors (see below), whose sum is σ = 26025468480. Its totient is φ = 4329758192.
The previous prime is 13001004361. The next prime is 13001004521. The reversal of 13001004402 is 20440010031.
It is a super-2 number, since 2×130010044022 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 970278 + ... + 983585.
It is an arithmetic number, because the mean of its divisors is an integer number (1626591780).
Almost surely, 213001004402 is an apocalyptic number.
13001004402 is an abundant number, since it is smaller than the sum of its proper divisors (13024464078).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001004402 is a wasteful number, since it uses less digits than its factorization.
13001004402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1954977.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 13001004402 its reverse (20440010031), we get a palindrome (33441014433).
The spelling of 13001004402 in words is "thirteen billion, one million, four thousand, four hundred two".
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