Base | Representation |
---|---|
bin | 11000001101110101… |
… | …11011110000001011 |
3 | 1020120001200221210112 |
4 | 30012322323300023 |
5 | 203111224424113 |
6 | 5550024504535 |
7 | 640114540505 |
oct | 140672736013 |
9 | 36501627715 |
10 | 13001014283 |
11 | 5571808504 |
12 | 262a01b14b |
13 | 12c266857a |
14 | 8b4950d75 |
15 | 5115a25a8 |
hex | 306ebbc0b |
13001014283 has 2 divisors, whose sum is σ = 13001014284. Its totient is φ = 13001014282.
The previous prime is 13001014259. The next prime is 13001014291. The reversal of 13001014283 is 38241010031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13001014283 - 26 = 13001014219 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13001014223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500507141 + 6500507142.
It is an arithmetic number, because the mean of its divisors is an integer number (6500507142).
Almost surely, 213001014283 is an apocalyptic number.
13001014283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001014283 is an equidigital number, since it uses as much as digits as its factorization.
13001014283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
The spelling of 13001014283 in words is "thirteen billion, one million, fourteen thousand, two hundred eighty-three".
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