13001021101 has 4 divisors (see below), whose sum is σ = 13566282912. Its totient is φ = 12435759292.

The previous prime is 13001021093. The next prime is 13001021119. The reversal of 13001021101 is 10112010031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10112010031 = 41 ⋅246634391.

It is a cyclic number.

It is not a de Polignac number, because 13001021101 - 2³ = 13001021093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001021161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282630871 + ... + 282630916.

It is an arithmetic number, because the mean of its divisors is an integer number (3391570728).

Almost surely, 2^13001021101 is an apocalyptic number.

It is an amenable number.

13001021101 is a deficient number, since it is larger than the sum of its proper divisors (565261811).

13001021101 is an equidigital number, since it uses as much as digits as its factorization.

13001021101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565261810.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 13001021101 its reverse (10112010031), we get a palindrome (23113031132).

The spelling of 13001021101 in words is "thirteen billion, one million, twenty-one thousand, one hundred one".