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13001031481 is a prime number
BaseRepresentation
bin11000001101110101…
…11111111100111001
31020120001201211101111
430012322333330321
5203111231001411
65550025120321
7640114641604
oct140672777471
936501654344
1013001031481
11557181a419
12262a0290a1
1312c2673349
148b495733b
155115a7721
hex306ebff39

13001031481 has 2 divisors, whose sum is σ = 13001031482. Its totient is φ = 13001031480.

The previous prime is 13001031437. The next prime is 13001031487. The reversal of 13001031481 is 18413010031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11559690256 + 1441341225 = 107516^2 + 37965^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13001031481 is a prime.

It is a super-2 number, since 2×130010314812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13001031487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500515740 + 6500515741.

It is an arithmetic number, because the mean of its divisors is an integer number (6500515741).

Almost surely, 213001031481 is an apocalyptic number.

It is an amenable number.

13001031481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001031481 is an equidigital number, since it uses as much as digits as its factorization.

13001031481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

The spelling of 13001031481 in words is "thirteen billion, one million, thirty-one thousand, four hundred eighty-one".