13001035001 has 2 divisors, whose sum is σ = 13001035002. Its totient is φ = 13001035000.

The previous prime is 13001034997. The next prime is 13001035027. The reversal of 13001035001 is 10053010031.

13001035001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8611840000 + 4389195001 = 92800^2 + 66251^2 .

It is a cyclic number.

It is not a de Polignac number, because 13001035001 - 2² = 13001034997 is a prime.

It is a super-2 number, since 2×13001035001² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13001035031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500517500 + 6500517501.

It is an arithmetic number, because the mean of its divisors is an integer number (6500517501).

Almost surely, 2^13001035001 is an apocalyptic number.

It is an amenable number.

13001035001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001035001 is an equidigital number, since it uses as much as digits as its factorization.

13001035001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45, while the sum is 14.

Adding to 13001035001 its reverse (10053010031), we get a palindrome (23054045032).

It can be divided in two parts, 1300 and 1035001, that added together give a palindrome (1036301).

The spelling of 13001035001 in words is "thirteen billion, one million, thirty-five thousand, one".