Base | Representation |
---|---|
bin | 111100100010100111… |
… | …0100000100001110011 |
3 | 110102120122121011101011 |
4 | 1321011032200201303 |
5 | 4112230133400120 |
6 | 135420451051351 |
7 | 12251531406634 |
oct | 1710516404163 |
9 | 412518534334 |
10 | 130010450035 |
11 | 50156567424 |
12 | 212442a0b57 |
13 | c34c0c319b |
14 | 6414a2988b |
15 | 35adc29c5a |
hex | 1e453a0873 |
130010450035 has 32 divisors (see below), whose sum is σ = 169695129600. Its totient is φ = 95257918080.
The previous prime is 130010449979. The next prime is 130010450047. The reversal of 130010450035 is 530054010031.
It is a happy number.
It is not a de Polignac number, because 130010450035 - 29 = 130010449523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130010449988 and 130010450015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2914026 + ... + 2958304.
It is an arithmetic number, because the mean of its divisors is an integer number (5302972800).
Almost surely, 2130010450035 is an apocalyptic number.
130010450035 is a deficient number, since it is larger than the sum of its proper divisors (39684679565).
130010450035 is a wasteful number, since it uses less digits than its factorization.
130010450035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45331.
The product of its (nonzero) digits is 900, while the sum is 22.
Adding to 130010450035 its reverse (530054010031), we get a palindrome (660064460066).
The spelling of 130010450035 in words is "one hundred thirty billion, ten million, four hundred fifty thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •