13001069935 has 16 divisors (see below), whose sum is σ = 17896334400. Its totient is φ = 8881871616.

The previous prime is 13001069933. The next prime is 13001069959. The reversal of 13001069935 is 53996010031.

It is a cyclic number.

It is not a de Polignac number, because 13001069935 - 2¹ = 13001069933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13001069894 and 13001069903.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001069933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 681030 + ... + 699859.

It is an arithmetic number, because the mean of its divisors is an integer number (1118520900).

Almost surely, 2^13001069935 is an apocalyptic number.

13001069935 is a deficient number, since it is larger than the sum of its proper divisors (4895264465).

13001069935 is a wasteful number, since it uses less digits than its factorization.

13001069935 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1381170.

The product of its (nonzero) digits is 21870, while the sum is 37.

Adding to 13001069935 its reverse (53996010031), we get a palindrome (66997079966).

The spelling of 13001069935 in words is "thirteen billion, one million, sixty-nine thousand, nine hundred thirty-five".