Base | Representation |
---|---|
bin | 11101100011111010001011… |
… | …100010110100110110011000 |
3 | 122001022221010012201202222200 |
4 | 131203322023202310312120 |
5 | 114020100012302243222 |
6 | 1140302121320050200 |
7 | 36245661544363653 |
oct | 3543721342646630 |
9 | 561287105652880 |
10 | 130011001212312 |
11 | 384753a0893930 |
12 | 126b9005303960 |
13 | 5770ca581557c |
14 | 24167cd2a689a |
15 | 1006d402c6eac |
hex | 763e8b8b4d98 |
130011001212312 has 384 divisors, whose sum is σ = 395514168192000. Its totient is φ = 38234569605120.
The previous prime is 130011001212233. The next prime is 130011001212371. The reversal of 130011001212312 is 213212100110031.
130011001212312 is a `hidden beast` number, since 1 + 30 + 0 + 110 + 0 + 1 + 212 + 312 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 22265967489 + ... + 22265973327.
It is an arithmetic number, because the mean of its divisors is an integer number (1029984813000).
Almost surely, 2130011001212312 is an apocalyptic number.
130011001212312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130011001212312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (197757084096000).
130011001212312 is an abundant number, since it is smaller than the sum of its proper divisors (265503166979688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130011001212312 is a wasteful number, since it uses less digits than its factorization.
130011001212312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7711 (or 7704 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 130011001212312 its reverse (213212100110031), we get a palindrome (343223101322343).
The spelling of 130011001212312 in words is "one hundred thirty trillion, eleven billion, one million, two hundred twelve thousand, three hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •