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130011033021521 is a prime number
BaseRepresentation
bin11101100011111010001101…
…011100001010110001010001
3122001022221012102120212000112
4131203322031130022301101
5114020100043423142041
61140302124413531105
736245662411636121
oct3543721534126121
9561287172525015
10130011033021521
113847540783a633
12126b9013aa3a95
135770cac2a1ba2
1424167d35c6c81
151006d42eabdeb
hex763e8d70ac51

130011033021521 has 2 divisors, whose sum is σ = 130011033021522. Its totient is φ = 130011033021520.

The previous prime is 130011033021491. The next prime is 130011033021601. The reversal of 130011033021521 is 125120330110031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105453695974225 + 24557337047296 = 10269065^2 + 4955536^2 .

It is a cyclic number.

It is not a de Polignac number, because 130011033021521 - 222 = 130011028827217 is a prime.

It is not a weakly prime, because it can be changed into another prime (130011033026521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005516510760 + 65005516510761.

It is an arithmetic number, because the mean of its divisors is an integer number (65005516510761).

Almost surely, 2130011033021521 is an apocalyptic number.

It is an amenable number.

130011033021521 is a deficient number, since it is larger than the sum of its proper divisors (1).

130011033021521 is an equidigital number, since it uses as much as digits as its factorization.

130011033021521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 130011033021521 its reverse (125120330110031), we get a palindrome (255131363131552).

The spelling of 130011033021521 in words is "one hundred thirty trillion, eleven billion, thirty-three million, twenty-one thousand, five hundred twenty-one".