130011103153 has 2 divisors, whose sum is σ = 130011103154. Its totient is φ = 130011103152.

The previous prime is 130011103109. The next prime is 130011103177. The reversal of 130011103153 is 351301110031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114952868209 + 15058234944 = 339047^2 + 122712^2 .

It is an emirp because it is prime and its reverse (351301110031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130011103153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130011103153.

It is not a weakly prime, because it can be changed into another prime (130011103753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005551576 + 65005551577.

It is an arithmetic number, because the mean of its divisors is an integer number (65005551577).

Almost surely, 2^130011103153 is an apocalyptic number.

It is an amenable number.

130011103153 is a deficient number, since it is larger than the sum of its proper divisors (1).

130011103153 is an equidigital number, since it uses as much as digits as its factorization.

130011103153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 130011103153 its reverse (351301110031), we get a palindrome (481312213184).

The spelling of 130011103153 in words is "one hundred thirty billion, eleven million, one hundred three thousand, one hundred fifty-three".