13001110440419 has 4 divisors (see below), whose sum is σ = 13001254969560. Its totient is φ = 13000965911280.

The previous prime is 13001110440397. The next prime is 13001110440463. The reversal of 13001110440419 is 91404401110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001110440419 - 2²⁸ = 13000842004963 is a prime.

It is a super-2 number, since 2×13001110440419² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13001110440391 and 13001110440400.

It is not an unprimeable number, because it can be changed into a prime (13001110440119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72129554 + ... + 72309575.

It is an arithmetic number, because the mean of its divisors is an integer number (3250313742390).

Almost surely, 2^{13001110440419} is an apocalyptic number.

13001110440419 is a deficient number, since it is larger than the sum of its proper divisors (144529141).

13001110440419 is an equidigital number, since it uses as much as digits as its factorization.

13001110440419 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144529140.

The product of its (nonzero) digits is 1728, while the sum is 29.

The spelling of 13001110440419 in words is "thirteen trillion, one billion, one hundred ten million, four hundred forty thousand, four hundred nineteen".