Base | Representation |
---|---|
bin | 1011110100110000111010… |
… | …0100011100100111100100 |
3 | 1201000220010201222202011110 |
4 | 2331030032210130213210 |
5 | 3201002233233043140 |
6 | 43352343325105020 |
7 | 2511204431240124 |
oct | 275141644344744 |
9 | 51026121882143 |
10 | 13001110440420 |
11 | 41628159a6053 |
12 | 155b8516b8170 |
13 | 733ccba5325b |
14 | 32d3856c0c84 |
15 | 1782c6dd1380 |
hex | bd30e91c9e4 |
13001110440420 has 48 divisors (see below), whose sum is σ = 36403769969280. Its totient is φ = 3466899856896.
The previous prime is 13001110440397. The next prime is 13001110440463. The reversal of 13001110440420 is 2404401110031.
13001110440420 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1414809 + ... + 5291871.
It is an arithmetic number, because the mean of its divisors is an integer number (758411874360).
Almost surely, 213001110440420 is an apocalyptic number.
13001110440420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13001110440420 is an abundant number, since it is smaller than the sum of its proper divisors (23402659528860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001110440420 is a wasteful number, since it uses less digits than its factorization.
13001110440420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3932964 (or 3932962 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 13001110440420 its reverse (2404401110031), we get a palindrome (15405511550451).
The spelling of 13001110440420 in words is "thirteen trillion, one billion, one hundred ten million, four hundred forty thousand, four hundred twenty".
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