Base | Representation |
---|---|
bin | 1011110100110000111010… |
… | …0100011100100111001101 |
3 | 1201000220010201222202010121 |
4 | 2331030032210130213031 |
5 | 3201002233233043042 |
6 | 43352343325104541 |
7 | 2511204431240062 |
oct | 275141644344715 |
9 | 51026121882117 |
10 | 13001110440397 |
11 | 41628159a6032 |
12 | 155b8516b8151 |
13 | 733ccba53241 |
14 | 32d3856c0c69 |
15 | 1782c6dd1367 |
hex | bd30e91c9cd |
13001110440397 has 2 divisors, whose sum is σ = 13001110440398. Its totient is φ = 13001110440396.
The previous prime is 13001110440371. The next prime is 13001110440463. The reversal of 13001110440397 is 79304401110031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12999911480521 + 1198959876 = 3605539^2 + 34626^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13001110440397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13001110240397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500555220198 + 6500555220199.
It is an arithmetic number, because the mean of its divisors is an integer number (6500555220199).
Almost surely, 213001110440397 is an apocalyptic number.
It is an amenable number.
13001110440397 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001110440397 is an equidigital number, since it uses as much as digits as its factorization.
13001110440397 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 34.
The spelling of 13001110440397 in words is "thirteen trillion, one billion, one hundred ten million, four hundred forty thousand, three hundred ninety-seven".
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