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130011133303200 = 25352374731150837
BaseRepresentation
bin11101100011111010010011…
…011010101101100110100000
3122001022221110102021200121210
4131203322103122231212200
5114020100300111200300
61140302142355150120
736245665040213412
oct3543722332554640
9561287412250553
10130011133303200
1138475459403756
12126b90415a5340
135770cc6cb3966
142416802a4c9b2
151006d4bbba050
hex763e936ad9a0

130011133303200 has 288 divisors, whose sum is σ = 443871031935744. Its totient is φ = 33014902026240.

The previous prime is 130011133303171. The next prime is 130011133303229. The reversal of 130011133303200 is 2303331110031.

It is an interprime number because it is at equal distance from previous prime (130011133303171) and next prime (130011133303229).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11401819 + ... + 19749018.

It is an arithmetic number, because the mean of its divisors is an integer number (1541218860888).

Almost surely, 2130011133303200 is an apocalyptic number.

130011133303200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130011133303200 is an abundant number, since it is smaller than the sum of its proper divisors (313859898632544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130011133303200 is a wasteful number, since it uses less digits than its factorization.

130011133303200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31150944 (or 31150931 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 130011133303200 its reverse (2303331110031), we get a palindrome (132314464413231).

The spelling of 130011133303200 in words is "one hundred thirty trillion, eleven billion, one hundred thirty-three million, three hundred three thousand, two hundred".