Base | Representation |
---|---|
bin | 11101100011111010010111… |
… | …011100111101011011110010 |
3 | 122001022221122010200002211012 |
4 | 131203322113130331123302 |
5 | 114020100414424014302 |
6 | 1140302153214150522 |
7 | 36245666521511603 |
oct | 3543722734753362 |
9 | 561287563602735 |
10 | 130011201001202 |
11 | 38475493642214 |
12 | 126b90601b2442 |
13 | 5771008027751 |
14 | 241680ba31daa |
15 | 1006d52adda52 |
hex | 763e9773d6f2 |
130011201001202 has 4 divisors (see below), whose sum is σ = 195016801501806. Its totient is φ = 65005600500600.
The previous prime is 130011201001069. The next prime is 130011201001217. The reversal of 130011201001202 is 202100102110031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 66223967871721 + 63787233129481 = 8137811^2 + 7986691^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32502800250299 + ... + 32502800250302.
Almost surely, 2130011201001202 is an apocalyptic number.
130011201001202 is a deficient number, since it is larger than the sum of its proper divisors (65005600500604).
130011201001202 is an equidigital number, since it uses as much as digits as its factorization.
130011201001202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65005600500603.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 130011201001202 its reverse (202100102110031), we get a palindrome (332111303111233).
The spelling of 130011201001202 in words is "one hundred thirty trillion, eleven billion, two hundred one million, one thousand, two hundred two".
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