1300112113122 has 32 divisors (see below), whose sum is σ = 3014752728960. Its totient is φ = 414528499440.

The previous prime is 1300112113121. The next prime is 1300112113141. The reversal of 1300112113122 is 2213112110031.

1300112113122 is a `hidden beast` number, since 130 + 0 + 11 + 211 + 312 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1300112113095 and 1300112113104.

It is not an unprimeable number, because it can be changed into a prime (1300112113121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 523393329 + ... + 523395812.

It is an arithmetic number, because the mean of its divisors is an integer number (94211022780).

Almost surely, 2^{1300112113122} is an apocalyptic number.

1300112113122 is an abundant number, since it is smaller than the sum of its proper divisors (1714640615838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300112113122 is a wasteful number, since it uses less digits than its factorization.

1300112113122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1046789175 (or 1046789169 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1300112113122 its reverse (2213112110031), we get a palindrome (3513224223153).

The spelling of 1300112113122 in words is "one trillion, three hundred billion, one hundred twelve million, one hundred thirteen thousand, one hundred twenty-two".