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130011301213200 = 24325211109713192269
BaseRepresentation
bin11101100011111010011101…
…011011001111010000010000
3122001022221220010020101211200
4131203322131123033100100
5114020101121102310300
61140302211154111200
736246002146346061
oct3543723533172020
9561287803211750
10130011301213200
1138475535168a50
12126b908987b500
135771022a138a4
14241681b07a568
151006d5b7d6200
hex763e9d6cf410

130011301213200 has 720 divisors, whose sum is σ = 493230716035200. Its totient is φ = 31451419238400.

The previous prime is 130011301213177. The next prime is 130011301213217. The reversal of 130011301213200 is 2312103110031.

130011301213200 is a `hidden beast` number, since 1 + 30 + 0 + 11 + 301 + 2 + 1 + 320 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 57298941666 + ... + 57298943934.

It is an arithmetic number, because the mean of its divisors is an integer number (685042661160).

Almost surely, 2130011301213200 is an apocalyptic number.

130011301213200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130011301213200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (246615358017600).

130011301213200 is an abundant number, since it is smaller than the sum of its proper divisors (363219414822000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130011301213200 is a wasteful number, since it uses less digits than its factorization.

130011301213200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4720 (or 4706 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 130011301213200 its reverse (2312103110031), we get a palindrome (132323404323231).

The spelling of 130011301213200 in words is "one hundred thirty trillion, eleven billion, three hundred one million, two hundred thirteen thousand, two hundred".