1300113230111 has 4 divisors (see below), whose sum is σ = 1302599106792. Its totient is φ = 1297627353432.

The previous prime is 1300113230089. The next prime is 1300113230131. The reversal of 1300113230111 is 1110323110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300113230111 - 2⁶ = 1300113230047 is a prime.

It is a super-2 number, since 2×1300113230111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300113230111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300113230131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1242937556 + ... + 1242938601.

It is an arithmetic number, because the mean of its divisors is an integer number (325649776698).

Almost surely, 2^{1300113230111} is an apocalyptic number.

1300113230111 is a deficient number, since it is larger than the sum of its proper divisors (2485876681).

1300113230111 is an equidigital number, since it uses as much as digits as its factorization.

1300113230111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2485876680.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1300113230111 its reverse (1110323110031), we get a palindrome (2410436340142).

The spelling of 1300113230111 in words is "one trillion, three hundred billion, one hundred thirteen million, two hundred thirty thousand, one hundred eleven".