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1300113230110 = 25177647724883
BaseRepresentation
bin10010111010110100110…
…010011000100100011110
311121021211010102010201221
4102322310302120210132
5132300112441330420
62433132550323554
7162634006055332
oct22726462304436
94537733363657
101300113230110
1146141402a6a2
1218bb793595ba
13957a56c0ac6
1446cd66217c2
1523c43d3ecaa
hex12eb4c9891e

1300113230110 has 16 divisors (see below), whose sum is σ = 2477862862416. Its totient is φ = 489454392448.

The previous prime is 1300113230089. The next prime is 1300113230131. The reversal of 1300113230110 is 110323110031.

It is an interprime number because it is at equal distance from previous prime (1300113230089) and next prime (1300113230131).

It is a super-2 number, since 2×13001132301102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3823862272 + ... + 3823862611.

It is an arithmetic number, because the mean of its divisors is an integer number (154866428901).

Almost surely, 21300113230110 is an apocalyptic number.

1300113230110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1300113230110 is a deficient number, since it is larger than the sum of its proper divisors (1177749632306).

1300113230110 is a wasteful number, since it uses less digits than its factorization.

1300113230110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7647724907.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1300113230110 its reverse (110323110031), we get a palindrome (1410436340141).

The spelling of 1300113230110 in words is "one trillion, three hundred billion, one hundred thirteen million, two hundred thirty thousand, one hundred ten".

Divisors: 1 2 5 10 17 34 85 170 7647724883 15295449766 38238624415 76477248830 130011323011 260022646022 650056615055 1300113230110