1300113444 has 96 divisors (see below), whose sum is σ = 3569319936. Its totient is φ = 360587520.

The previous prime is 1300113443. The next prime is 1300113457. The reversal of 1300113444 is 4443110031.

It is a super-2 number, since 2×1300113444² = 3380589934539082272, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a self number, because there is not a number n which added to its sum of digits gives 1300113444.

It is not an unprimeable number, because it can be changed into a prime (1300113443) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 780957 + ... + 782619.

It is an arithmetic number, because the mean of its divisors is an integer number (37180416).

Almost surely, 2^1300113444 is an apocalyptic number.

1300113444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300113444, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1784659968).

1300113444 is an abundant number, since it is smaller than the sum of its proper divisors (2269206492).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300113444 is a wasteful number, since it uses less digits than its factorization.

1300113444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1945 (or 1943 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1300113444 is about 36057.0859055471. The cubic root of 1300113444 is about 1091.4246287978.

Adding to 1300113444 its reverse (4443110031), we get a palindrome (5743223475).

The spelling of 1300113444 in words is "one billion, three hundred million, one hundred thirteen thousand, four hundred forty-four".