Base | Representation |
---|---|
bin | 11000001101110110… |
… | …11010011100101100 |
3 | 1020120001221100021011 |
4 | 30012323122130230 |
5 | 203111242440022 |
6 | 5550031315004 |
7 | 640115603200 |
oct | 140673323454 |
9 | 36501840234 |
10 | 13001140012 |
11 | 5571893a13 |
12 | 262a07ba64 |
13 | 12c26b0873 |
14 | 8b4984b00 |
15 | 5115c9977 |
hex | 306eda72c |
13001140012 has 18 divisors (see below), whose sum is σ = 26466606852. Its totient is φ = 5571917064.
The previous prime is 13001140007. The next prime is 13001140039. The reversal of 13001140012 is 21004110031.
It is a super-2 number, since 2×130011400122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13001139974 and 13001140001.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 33165978 + ... + 33166369.
Almost surely, 213001140012 is an apocalyptic number.
It is an amenable number.
13001140012 is an abundant number, since it is smaller than the sum of its proper divisors (13465466840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001140012 is a wasteful number, since it uses less digits than its factorization.
13001140012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66332365 (or 66332356 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 13001140012 its reverse (21004110031), we get a palindrome (34005250043).
The spelling of 13001140012 in words is "thirteen billion, one million, one hundred forty thousand, twelve".
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