Base | Representation |
---|---|
bin | 111100100010101001… |
… | …0001011010001010011 |
3 | 110102120201102000022102 |
4 | 1321011102023101103 |
5 | 4112230410132124 |
6 | 135420523431015 |
7 | 12251542523102 |
oct | 1710522132123 |
9 | 412521360272 |
10 | 130011411539 |
11 | 50157063859 |
12 | 2124468546b |
13 | c34c36ba19 |
14 | 6414bda039 |
15 | 35add69aae |
hex | 1e4548b453 |
130011411539 has 2 divisors, whose sum is σ = 130011411540. Its totient is φ = 130011411538.
The previous prime is 130011411529. The next prime is 130011411559. The reversal of 130011411539 is 935114110031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130011411539 - 224 = 129994634323 is a prime.
It is not a weakly prime, because it can be changed into another prime (130011411529) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005705769 + 65005705770.
It is an arithmetic number, because the mean of its divisors is an integer number (65005705770).
Almost surely, 2130011411539 is an apocalyptic number.
130011411539 is a deficient number, since it is larger than the sum of its proper divisors (1).
130011411539 is an equidigital number, since it uses as much as digits as its factorization.
130011411539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 29.
The spelling of 130011411539 in words is "one hundred thirty billion, eleven million, four hundred eleven thousand, five hundred thirty-nine".
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