Base | Representation |
---|---|
bin | 11101100011111010101001… |
… | …011001100101011100101110 |
3 | 122001022222102010020211112002 |
4 | 131203322221121211130232 |
5 | 114020102024014401124 |
6 | 1140302243132012302 |
7 | 36246010136043425 |
oct | 3543725131453456 |
9 | 561288363224462 |
10 | 130011502106414 |
11 | 38475628600aa5 |
12 | 126b9125001092 |
13 | 5771055521606 |
14 | 2416839a122bc |
15 | 1006d6e26a0ae |
hex | 763ea966572e |
130011502106414 has 8 divisors (see below), whose sum is σ = 195017822459328. Its totient is φ = 65005561286640.
The previous prime is 130011502106411. The next prime is 130011502106417. The reversal of 130011502106414 is 414601205110031.
It is an interprime number because it is at equal distance from previous prime (130011502106411) and next prime (130011502106417).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130011502106411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94025342 + ... + 95398049.
It is an arithmetic number, because the mean of its divisors is an integer number (24377227807416).
Almost surely, 2130011502106414 is an apocalyptic number.
130011502106414 is a deficient number, since it is larger than the sum of its proper divisors (65006320352914).
130011502106414 is a wasteful number, since it uses less digits than its factorization.
130011502106414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 189766570.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 130011502106414 its reverse (414601205110031), we get a palindrome (544612707216445).
The spelling of 130011502106414 in words is "one hundred thirty trillion, eleven billion, five hundred two million, one hundred six thousand, four hundred fourteen".
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