Base | Representation |
---|---|
bin | 11101100011111011000111… |
… | …001101110011000110110000 |
3 | 122001100000200222111222112112 |
4 | 131203323013031303012300 |
5 | 114020104040044124404 |
6 | 1140302404521344452 |
7 | 36246025421643323 |
oct | 3543730715630660 |
9 | 561300628458475 |
10 | 130012002333104 |
11 | 38475864a02791 |
12 | 126b9244638128 |
13 | 5771105055938 |
14 | 24168862267ba |
15 | 1006d9d12a56e |
hex | 763ec73731b0 |
130012002333104 has 10 divisors (see below), whose sum is σ = 251898254520420. Its totient is φ = 65006001166544.
The previous prime is 130012002333089. The next prime is 130012002333113. The reversal of 130012002333104 is 401333200210031.
It is a self number, because there is not a number n which added to its sum of digits gives 130012002333104.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4062875072894 + ... + 4062875072925.
It is an arithmetic number, because the mean of its divisors is an integer number (25189825452042).
Almost surely, 2130012002333104 is an apocalyptic number.
It is an amenable number.
130012002333104 is a deficient number, since it is larger than the sum of its proper divisors (121886252187316).
130012002333104 is an equidigital number, since it uses as much as digits as its factorization.
130012002333104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8125750145827 (or 8125750145821 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 130012002333104 its reverse (401333200210031), we get a palindrome (531345202543135).
The spelling of 130012002333104 in words is "one hundred thirty trillion, twelve billion, two million, three hundred thirty-three thousand, one hundred four".
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