Base | Representation |
---|---|
bin | 11101100011111011001000… |
… | …010001100101000010000011 |
3 | 122001100000202012221200212001 |
4 | 131203323020101211002003 |
5 | 114020104104121220001 |
6 | 1140302410354244431 |
7 | 36246026025655441 |
oct | 3543731021450203 |
9 | 561300665850761 |
10 | 130012020101251 |
11 | 38475873a39202 |
12 | 126b924a586717 |
13 | 5771108937232 |
14 | 241688872db91 |
15 | 1006d9e98a001 |
hex | 763ec8465083 |
130012020101251 has 2 divisors, whose sum is σ = 130012020101252. Its totient is φ = 130012020101250.
The previous prime is 130012020101191. The next prime is 130012020101281. The reversal of 130012020101251 is 152101020210031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130012020101251 - 223 = 130012011712643 is a prime.
It is not a weakly prime, because it can be changed into another prime (130012020101281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006010050625 + 65006010050626.
It is an arithmetic number, because the mean of its divisors is an integer number (65006010050626).
Almost surely, 2130012020101251 is an apocalyptic number.
130012020101251 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012020101251 is an equidigital number, since it uses as much as digits as its factorization.
130012020101251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 130012020101251 its reverse (152101020210031), we get a palindrome (282113040311282).
The spelling of 130012020101251 in words is "one hundred thirty trillion, twelve billion, twenty million, one hundred one thousand, two hundred fifty-one".
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