Base | Representation |
---|---|
bin | 11000001101110111… |
… | …01001110111001011 |
3 | 1020120002001112212111 |
4 | 30012323221313023 |
5 | 203111302000042 |
6 | 5550032523151 |
7 | 640116255232 |
oct | 140673516713 |
9 | 36502045774 |
10 | 13001203147 |
11 | 5571927399 |
12 | 262a0b04b7 |
13 | 12c270351a |
14 | 8b499db19 |
15 | 5115dd517 |
hex | 306ee9dcb |
13001203147 has 2 divisors, whose sum is σ = 13001203148. Its totient is φ = 13001203146.
The previous prime is 13001203109. The next prime is 13001203199. The reversal of 13001203147 is 74130210031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13001203147 - 223 = 12992814539 is a prime.
It is not a weakly prime, because it can be changed into another prime (13001203547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500601573 + 6500601574.
It is an arithmetic number, because the mean of its divisors is an integer number (6500601574).
Almost surely, 213001203147 is an apocalyptic number.
13001203147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001203147 is an equidigital number, since it uses as much as digits as its factorization.
13001203147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 13001203147 its reverse (74130210031), we get a palindrome (87131413178).
The spelling of 13001203147 in words is "thirteen billion, one million, two hundred three thousand, one hundred forty-seven".
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