130012042019 has 2 divisors, whose sum is σ = 130012042020. Its totient is φ = 130012042018.

The previous prime is 130012041983. The next prime is 130012042031. The reversal of 130012042019 is 910240210031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130012042019 - 2⁸ = 130012041763 is a prime.

It is a super-2 number, since 2×130012042019² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130012041985 and 130012042003.

It is not a weakly prime, because it can be changed into another prime (130012042079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006021009 + 65006021010.

It is an arithmetic number, because the mean of its divisors is an integer number (65006021010).

Almost surely, 2^130012042019 is an apocalyptic number.

130012042019 is a deficient number, since it is larger than the sum of its proper divisors (1).

130012042019 is an equidigital number, since it uses as much as digits as its factorization.

130012042019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 130012042019 in words is "one hundred thirty billion, twelve million, forty-two thousand, nineteen".