Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0110011010110100011 |
3 | 110102120202200222201002 |
4 | 1321011110303112203 |
5 | 4112231044200003 |
6 | 135420550302215 |
7 | 12251551421222 |
oct | 1710524632643 |
9 | 412522628632 |
10 | 130012100003 |
11 | 50157494035 |
12 | 2124495796b |
13 | c34c5501b6 |
14 | 6414d38cb9 |
15 | 35ade53a88 |
hex | 1e455335a3 |
130012100003 has 2 divisors, whose sum is σ = 130012100004. Its totient is φ = 130012100002.
The previous prime is 130012099981. The next prime is 130012100039. The reversal of 130012100003 is 300001210031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130012100003 - 26 = 130012099939 is a prime.
It is a super-2 number, since 2×1300121000032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130012700003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006050001 + 65006050002.
It is an arithmetic number, because the mean of its divisors is an integer number (65006050002).
Almost surely, 2130012100003 is an apocalyptic number.
130012100003 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012100003 is an equidigital number, since it uses as much as digits as its factorization.
130012100003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 130012100003 its reverse (300001210031), we get a palindrome (430013310034).
The spelling of 130012100003 in words is "one hundred thirty billion, twelve million, one hundred thousand, three".
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