Search a number
-
+
13001210001302 = 26500605000651
BaseRepresentation
bin1011110100110001010010…
…0000001111011110010110
31201000220101200022222000112
42331030110200033132112
53201002434230020202
643352401243043022
72511210050423105
oct275142440173626
951026350288015
1013001210001302
114162867117676
12155b87ab10472
13734016571c13
1432d3949da03c
151782d09eab52
hexbd31480f796

13001210001302 has 4 divisors (see below), whose sum is σ = 19501815001956. Its totient is φ = 6500605000650.

The previous prime is 13001210001223. The next prime is 13001210001313. The reversal of 13001210001302 is 20310001210031.

13001210001302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×130012100013022 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250302500324 + ... + 3250302500327.

It is an arithmetic number, because the mean of its divisors is an integer number (4875453750489).

Almost surely, 213001210001302 is an apocalyptic number.

13001210001302 is a deficient number, since it is larger than the sum of its proper divisors (6500605000654).

13001210001302 is an equidigital number, since it uses as much as digits as its factorization.

13001210001302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6500605000653.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13001210001302 its reverse (20310001210031), we get a palindrome (33311211211333).

The spelling of 13001210001302 in words is "thirteen trillion, one billion, two hundred ten million, one thousand, three hundred two".

Divisors: 1 2 6500605000651 13001210001302