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130012114 = 265006057
BaseRepresentation
bin1111011111111…
…01001111010010
3100001122022002111
413233331033102
5231240341424
620522335534
73136041031
oct757751722
9301568074
10130012114
1167430031
123765a5aa
1320c2115b
14133a4718
15b632194
hex7bfd3d2

130012114 has 4 divisors (see below), whose sum is σ = 195018174. Its totient is φ = 65006056.

The previous prime is 130012111. The next prime is 130012139. The reversal of 130012114 is 411210031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411210031 = 2317878697.

It can be written as a sum of positive squares in only one way, i.e., 127306089 + 2706025 = 11283^2 + 1645^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130012094 and 130012103.

It is not an unprimeable number, because it can be changed into a prime (130012111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32503027 + ... + 32503030.

Almost surely, 2130012114 is an apocalyptic number.

130012114 is a deficient number, since it is larger than the sum of its proper divisors (65006060).

130012114 is an equidigital number, since it uses as much as digits as its factorization.

130012114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65006059.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 130012114 is about 11402.2854726585. The cubic root of 130012114 is about 506.5954365663.

Adding to 130012114 its reverse (411210031), we get a palindrome (541222145).

The spelling of 130012114 in words is "one hundred thirty million, twelve thousand, one hundred fourteen".

Divisors: 1 2 65006057 130012114