Base | Representation |
---|---|
bin | 11101100011111011010100… |
… | …111010010111011101000001 |
3 | 122001100001021222220101002002 |
4 | 131203323110322113131001 |
5 | 114020110022410321004 |
6 | 1140302443410433345 |
7 | 36246034212051332 |
oct | 3543732472273501 |
9 | 561301258811062 |
10 | 130012232120129 |
11 | 38475972690117 |
12 | 126b92a9592855 |
13 | 577114083bca8 |
14 | 24168a8960289 |
15 | 1006db33ba61e |
hex | 763ed4e97741 |
130012232120129 has 2 divisors, whose sum is σ = 130012232120130. Its totient is φ = 130012232120128.
The previous prime is 130012232120077. The next prime is 130012232120159. The reversal of 130012232120129 is 921021232210031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116624880490000 + 13387351630129 = 10799300^2 + 3658873^2 .
It is a cyclic number.
It is not a de Polignac number, because 130012232120129 - 244 = 112420046075713 is a prime.
It is not a weakly prime, because it can be changed into another prime (130012232120159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006116060064 + 65006116060065.
It is an arithmetic number, because the mean of its divisors is an integer number (65006116060065).
Almost surely, 2130012232120129 is an apocalyptic number.
It is an amenable number.
130012232120129 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012232120129 is an equidigital number, since it uses as much as digits as its factorization.
130012232120129 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 130012232120129 in words is "one hundred thirty trillion, twelve billion, two hundred thirty-two million, one hundred twenty thousand, one hundred twenty-nine".
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