Base | Representation |
---|---|
bin | 1011110100110001010111… |
… | …0001000110111100010111 |
3 | 1201000220110011012222012100 |
4 | 2331030111301012330113 |
5 | 3201003010141400043 |
6 | 43352403321253143 |
7 | 2511210425544003 |
oct | 275142561067427 |
9 | 51026404188170 |
10 | 13001231200023 |
11 | 4162878086580 |
12 | 155b8860341b3 |
13 | 73401aa84b41 |
14 | 32d397757703 |
15 | 1782d27d6cd3 |
hex | bd315c46f17 |
13001231200023 has 24 divisors (see below), whose sum is σ = 21565040590080. Its totient is φ = 7464821740560.
The previous prime is 13001231199961. The next prime is 13001231200037. The reversal of 13001231200023 is 32000213210031.
It is not a de Polignac number, because 13001231200023 - 217 = 13001231068951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13001231199969 and 13001231200005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13001231200523) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3455934111 + ... + 3455937872.
It is an arithmetic number, because the mean of its divisors is an integer number (898543357920).
Almost surely, 213001231200023 is an apocalyptic number.
13001231200023 is a deficient number, since it is larger than the sum of its proper divisors (8563809390057).
13001231200023 is a wasteful number, since it uses less digits than its factorization.
13001231200023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6911872019 (or 6911872016 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13001231200023 its reverse (32000213210031), we get a palindrome (45001444410054).
The spelling of 13001231200023 in words is "thirteen trillion, one billion, two hundred thirty-one million, two hundred thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •