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1300124212424 = 23863881213751
BaseRepresentation
bin10010111010110101011…
…100010001110011001000
311121021211220002002122022
4102322311130101303020
5132300123244244144
62433134021544012
7162634201315622
oct22726534216310
94537756062568
101300124212424
1146141a250894
1218bb80b75008
13957a7a6780b
1446cd7c7dc12
1523c44cadcee
hex12eb5711cc8

1300124212424 has 32 divisors (see below), whose sum is σ = 2443339261440. Its totient is φ = 648568800000.

The previous prime is 1300124212417. The next prime is 1300124212441. The reversal of 1300124212424 is 4242124210031.

It is a super-2 number, since 2×13001242124242 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300124212393 and 1300124212402.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5975549 + ... + 6189299.

It is an arithmetic number, because the mean of its divisors is an integer number (76354351920).

Almost surely, 21300124212424 is an apocalyptic number.

It is an amenable number.

1300124212424 is a deficient number, since it is larger than the sum of its proper divisors (1143215049016).

1300124212424 is a wasteful number, since it uses less digits than its factorization.

1300124212424 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215501 (or 215497 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 1300124212424 its reverse (4242124210031), we get a palindrome (5542248422455).

The spelling of 1300124212424 in words is "one trillion, three hundred billion, one hundred twenty-four million, two hundred twelve thousand, four hundred twenty-four".

Divisors: 1 2 4 8 863 881 1726 1762 3452 3524 6904 7048 213751 427502 760303 855004 1520606 1710008 3041212 6082424 184467113 188314631 368934226 376629262 737868452 753258524 1475736904 1506517048 162515526553 325031053106 650062106212 1300124212424