Base | Representation |
---|---|
bin | 11101100011111100000101… |
… | …000101110011010101101110 |
3 | 122001100010101022212110221200 |
4 | 131203330011011303111232 |
5 | 114020113201322034202 |
6 | 1140303055523310330 |
7 | 36246063225402300 |
oct | 3543740505632556 |
9 | 561303338773850 |
10 | 130013040424302 |
11 | 38476247982aa2 |
12 | 126b949421b3a6 |
13 | 577123c13b899 |
14 | 241694404b970 |
15 | 1006e0e332e1c |
hex | 763f0517356e |
130013040424302 has 72 divisors (see below), whose sum is σ = 329496348314952. Its totient is φ = 36941353192800.
The previous prime is 130013040424279. The next prime is 130013040424373. The reversal of 130013040424302 is 203424040310031.
130013040424302 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 13 + 0 + 404 + 243 + 0 + 2 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 407042224 + ... + 407361507.
It is an arithmetic number, because the mean of its divisors is an integer number (4576338171041).
Almost surely, 2130013040424302 is an apocalyptic number.
130013040424302 is an abundant number, since it is smaller than the sum of its proper divisors (199483307890650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130013040424302 is a wasteful number, since it uses less digits than its factorization.
130013040424302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 814403934 (or 814403924 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 130013040424302 its reverse (203424040310031), we get a palindrome (333437080734333).
The spelling of 130013040424302 in words is "one hundred thirty trillion, thirteen billion, forty million, four hundred twenty-four thousand, three hundred two".
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