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130013040430034 = 265006520215017
BaseRepresentation
bin11101100011111100000101…
…000101110100101111010010
3122001100010101022212202210222
4131203330011011310233102
5114020113201322230114
61140303055523353042
736246063225425066
oct3543740505645722
9561303338782728
10130013040430034
1138476247987333
12126b9494222782
13577123c141388
14241694404daa6
151006e0e33498e
hex763f05174bd2

130013040430034 has 4 divisors (see below), whose sum is σ = 195019560645054. Its totient is φ = 65006520215016.

The previous prime is 130013040430027. The next prime is 130013040430069. The reversal of 130013040430034 is 430034040310031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 83251992808009 + 46761047622025 = 9124253^2 + 6838205^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130013040429985 and 130013040430012.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32503260107507 + ... + 32503260107510.

Almost surely, 2130013040430034 is an apocalyptic number.

130013040430034 is a deficient number, since it is larger than the sum of its proper divisors (65006520215020).

130013040430034 is an equidigital number, since it uses as much as digits as its factorization.

130013040430034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65006520215019.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 130013040430034 its reverse (430034040310031), we get a palindrome (560047080740065).

The spelling of 130013040430034 in words is "one hundred thirty trillion, thirteen billion, forty million, four hundred thirty thousand, thirty-four".

Divisors: 1 2 65006520215017 130013040430034