Search a number
-
+
130013101303 = 608921352127
BaseRepresentation
bin111100100010101100…
…0100111110011110111
3110102120211120212020021
41321011120213303313
54112231323220203
6135421023550011
712251563061401
oct1710530476367
9412524525207
10130013101303
1150158008358
122124515b307
13c34c810b97
146415119b71
1535ae0a05bd
hex1e45627cf7

130013101303 has 4 divisors (see below), whose sum is σ = 130034459520. Its totient is φ = 129991743088.

The previous prime is 130013101249. The next prime is 130013101327. The reversal of 130013101303 is 303101310031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130013101303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130013101003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10669975 + ... + 10682152.

It is an arithmetic number, because the mean of its divisors is an integer number (32508614880).

Almost surely, 2130013101303 is an apocalyptic number.

130013101303 is a deficient number, since it is larger than the sum of its proper divisors (21358217).

130013101303 is an equidigital number, since it uses as much as digits as its factorization.

130013101303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21358216.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 130013101303 its reverse (303101310031), we get a palindrome (433114411334).

The spelling of 130013101303 in words is "one hundred thirty billion, thirteen million, one hundred one thousand, three hundred three".

Divisors: 1 6089 21352127 130013101303