Base | Representation |
---|---|
bin | 111100100010101100… |
… | …0100111110011000001 |
3 | 110102120211120212011021 |
4 | 1321011120213303001 |
5 | 4112231323214444 |
6 | 135421023545441 |
7 | 12251563061263 |
oct | 1710530476301 |
9 | 412524525137 |
10 | 130013101249 |
11 | 50158008309 |
12 | 2124515b281 |
13 | c34c810b55 |
14 | 6415119b33 |
15 | 35ae0a0584 |
hex | 1e45627cc1 |
130013101249 has 2 divisors, whose sum is σ = 130013101250. Its totient is φ = 130013101248.
The previous prime is 130013101241. The next prime is 130013101327. The reversal of 130013101249 is 942101310031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124820890000 + 5192211249 = 353300^2 + 72057^2 .
It is a cyclic number.
It is not a de Polignac number, because 130013101249 - 23 = 130013101241 is a prime.
It is not a weakly prime, because it can be changed into another prime (130013101241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006550624 + 65006550625.
It is an arithmetic number, because the mean of its divisors is an integer number (65006550625).
Almost surely, 2130013101249 is an apocalyptic number.
It is an amenable number.
130013101249 is a deficient number, since it is larger than the sum of its proper divisors (1).
130013101249 is an equidigital number, since it uses as much as digits as its factorization.
130013101249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 130013101249 in words is "one hundred thirty billion, thirteen million, one hundred one thousand, two hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •